-2/3x^2+24=0

Solution for -2/3x^2+24=0 equation:

-2/3x^2+24=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


24*3x^2-2=0

Wy multiply elements

72x^2-2=0

a = 72; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·72·(-2)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*72}=\frac{-24}{144}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*72}=\frac{24}{144}
=1/6
$